Iz^2+(1+i)*z=0

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Solution for Iz^2+(1+i)*z=0 equation: 


Simplifying
Iz2 + (1 + i) * z = 0

Reorder the terms for easier multiplication:
z2I + z(1 + i) = 0
z2I + (1 * z + i * z) = 0

Reorder the terms:
z2I + (iz + 1z) = 0
z2I + (iz + 1z) = 0

Reorder the terms:
iz + 1z + z2I = 0

Solving
iz + 1z + z2I = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1z' to each side of the equation.
iz + 1z + -1z + z2I = 0 + -1z

Combine like terms: 1z + -1z = 0
iz + 0 + z2I = 0 + -1z
iz + z2I = 0 + -1z
Remove the zero:
iz + z2I = -1z

Add '-1z2I' to each side of the equation.
iz + z2I + -1z2I = -1z + -1z2I

Combine like terms: z2I + -1z2I = 0
iz + 0 = -1z + -1z2I
iz = -1z + -1z2I

Divide each side by 'z'.
i = -1 + -1zI

Simplifying
i = -1 + -1zI

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